Question

If a calculated Coefficient of Interference (I) of +0.55 were obtained for a linkage group, it would indicate a. positive interference, where 55 % of the double crossovers that are expected are not seen b. positive interference, where 45 % of the double crossovers that are expected are not seen c. positive interference, where 55% more double crossovers are seen than are expected d. positive interference, where 45% more double crossovers are seen than are expected Compulsive channel switching (i.e. channel surfing) is found to be caused by a recessive (but highly prevalent) gene on the X chromosome(cs). Also located on the X chromosome are two other recessive genes - one that causes an addiction to watching football on TV (fba), and one that causes excessive burping in public (bp). The location of these genes on the X chromosome are 25 (cs/cs^+), 43 (fba/fba^+) and 76 (bp/bp^+) map units. The level of interference over this linkage group (i.e. the Coefficient of Interference) is 0.15. A normal female has the genotype cs^+, fba bp^+/cs fba^+ bp. What is the probability that she will produce a gamete that contains all three recessive alleles? a. 0.025 b. 0.05 c. 0.15 d. 0.33 e. 0.85

Answer 1

6. The answer is A. Positive interference, where 55% of the double crossovers that are expected are not seen.

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