SOLUTION :
y = f(x) = 2x^2 + x - 3
=> f’ (x) = 4x + 1
a.
Now,
f’ (x) = dy / dx ≈ ∆y / ∆x
=> ∆y ≈ f’ (x) ∆x
=> ∆y (at x = 2, ∆x = - 0.03) is = (4(2) + 1) * (- 0.03)
=> ∆y = - 0.27 (ANSWER).
b.
dy = f’(x) dx = (4x + 1) dx
So, dy (at x = 2 and dx = ∆x = - 0.03) is = (4*2 + 1)*(-0.03)
=> dy = - 0.27 (ANSWER).
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