SOLUTION :
y = 3 x^3.
=> f’ (x) = 9 x^2
=> f’ (at x = 3) = 9 * (3)^2 = 81 (ANSWER).
Now,
f’ (x) = dy / dx ≈ ∆y / ∆x
=> ∆y ≈ f’ (x) ∆x
=> ∆y (at x = 3, ∆x = 0.02) = 9 *(3)^2 * 0.02
=> ∆y = 1.62 (ANSWER).
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