S1) FROM the given data,
revesre eq1 + eq2 = desired equation.
so that,
(1/k1)*(k2) = Ke
Ke = (1/(1.8*10^25))*(2.0*10^28)
= 1.11*10^3
S2)
a) CO2(g) + H2(g) <=====> CO(g) + H2O(g)
initial 0.18 M 0.18 M - -
change -x -x x x
equil 0.18-x 0.18-x x x
Kc = [CO][H2O]/[CO2][H2]
1260 = (X^2/((0.18-X)^2)
X = 0.175
AT equilibrium,
[CO2] = 0.18-0.175 = 0.005 M
[H2] = 0.18-0.175 = 0.005 M
[CO] = X = 0.175 M
[H2O] = X = 0.175 M
b) CO2(g) + H2(g) <=====> CO(g) + H2O(g)
initial 0.18 M 0.18 M - -
change -0.144 M -0.144 M +0.144 M +0.144 M
equil 0.036 0.036 0.144 M 0.144 M
Kc = [CO][H2O]/[CO2][H2]
= (0.144*0.144)/(0.036*0.036)
= 16
show clear Part Il Short Answer Questions (36 pts.) (Write legible and coherent anawer s sequence...
please write legible. answer all questions.
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Please help with solving Question 1 (A-C) Thank you!
Unless otherwise specified in the problem, you may assume that all solutions are at 25°C. 1. 50.0 mL of a pH 6.00 carbonic acid buffer is titrated with 0.2857 M NaOH, requiring 17.47 mL to reach the second equivalence point. a. Calculate the molarity of carbonic acid and bicarbonate in the original buffer. Carbonic acid: Bicarbonate: b. Calculate the pH of the solution after a total of 100.0 mL of 0.2857...