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A company that sells an online course aimed at helping high-school students improve their SAT scores has claimed that SAT sco

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Answer #1

Level of significance is 0.05

P(Z>z)=0.95

z=1.645

z=\frac{X-\mu}{\sigma/\sqrt{n}}

1.645=\frac{X-90}{30/\sqrt{100}}

X=90+(1.645*30/\sqrt{100})

=90+4.935=94.935

Answer is

D. Reject the null hypothesis if SAT improvement is >94.935 points

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