Question

6. Which of the following is not a true of the electric fields? a. The electric field is a vector quantity. b. The electric field is produced by charges. Two electric field lines may only cross at right angles. d. The electric field points from positive charges toward negative charges. ! All of the above are properties of the electric field. 7. Find the electric field (magnitude and direction) 2 in from an electron (charge of -1.6 x 10-19 C). 3.6 10-10 N/C toward the electron 3.6 10-10 N/C away from the electron 7.2 x 10-10 N/C toward the electron 4. 7.2 x 10-10 N/C away from the electron 3.6 x 10-9 N/C toward the electron 8.99x10m ax10 -1.6716-14 m 8. A point charge, q, experiences an electric force, F, when placed at a certain location in a field E. The point charge is replaced with a new one of charge new = 24 at the same location. What is the electric field, new, at the location of the new charge? a. Enew = 2E b. Enew = -2 c. Enew = 1/2 d. Emex = -7/2 fa Enew = Ē 9. The electric field a distance from a given point charge has magnitude E. At what dis- tance from the point charge does the field have magnitude E/4? & r/4 r/2 c. ar der e 16 10. When we worked out the electric field of a ring on a point a distance z above the center of the ring we found it had only a component perpendicular to the ring's plane that is only a 2 component. Why would this be true? Each differentinl charge element only produced a field in the z direction A. By symmetry the radial components canceled, leaving only the component The x and y components combine to produce only a 2 component No reason, sometimes physics is crazy like that. None of the above

Answer 1

tric of field Electric lines may interesect at any angle s wrong @ besides © Mo-7 -6x1019 r2 = PM - I & - EE un Eo ra ax109 x 1.6410-19 -10 = 3.6x10 towcucds electron. No 8 It will be same because source chatge not on electric field test charge. depends on Enew = ? . No-q Er kq 2 R2 Ato - 10 (6) By symmetocy, the dez radial components dErde dEx dEx. Hae cancelled, leaving only the e-component. Please look at the digram.