Enter your answer in the provided box. A 24.90-g sample of an alloy at 93.00 degree...

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Answer 1

Answer #1

Heat lost by the alloy= Heat gained by the calorimeter

m_alloyc_alloydeltaT_alloy = m_caloriec_calorideltaT_calorie

24.90g*c_alloy*(93-31.10)C = 50g*9.20J/K*(304.1-295)K

24.90g*61.9C*c_alloy =50g*9.1K*9.20J/K

1541.31Cg*c_alloy=4186Jg

c_alloy = 2.72J/C=2.72J/C /24.90g = 0.11J/Cg

Answer 2

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