Question

Enter your answer in the provided box. When 24.90 mL of 0.5000 M H SO, is added to 24.90 mL of 1.000 M KOH in a coffee-cup calorimeter at 23.50°C, the temperature rises to 30.17°C. Calculate AH of this reaction. (Assume that the total volume is the sum of the individual volumes and that the density and specific heat capacity of the solution are the same as for pure water.) (d for water -1.00 g/mL; c for wateľ= 4.184 J/g.°C.) kJ/mol H2SO4

Answer 1

Total volume of the solution = vol. of H₂ 504 von OT KOH 24.9 mL + 24.9mL = 49.8 mL- Temperature increases - tinal temor - initial tempo = (30.17°C - 23.50°C) = 6.67°c mass Density mass = Density & volume volume son mass of the soluion=(191m x 49.8mL) = 49.8 g specific heat capauty = 4.18 4 J/g.oc son tor lg solution 4.184 I neat is required 4.189x4908) eat & for rising ie. & & ic. 4 49.8g " = 208. 3632 J 208-36325 heat tor 49.8 g som Now, pe rising need u. 6.67% « ( 208.3632 x 6.67) neat & n. 1389.78 T so. 1389.78 J heat is given by the reaction to the son.

Now, 0.5 M 1000 mL H₂SO4 means H2SO4 son contains 0.5 mole H2SO4 Hence. 24.9 mL H₂SO4 sol 0.5 x 24.9 mile H₂SO4 1000 = 0. 01245 mole H₂50g- Soo 0.01245 mole H₂SO4 reacts to give 1389.78 J heat 1389.78 J heat 0.01245 = 1116289.95 neat = 1116.2899x1037 neat = 1116.2899 kJ neat ~ 1116.29 kJ neat sog 4H = 1116.29 kJ/mol H₂SO4