Homework Answers
H2SO4 + 2KOH --------------> K2So4 + 2H2O
25.3x0.5=12.65 25.3x0.1= 25.3 0 0 initial mmoles
0 0 25.3 25.3 after rxn
thus mmoles of H2O formed = 25.3
Now heat given during rxn = mass of water x specific heat x rise in temperature
=(25.3+25.3)g x 4.184J/g.K x (30.17-23.5) K
=1412.11 J
If 25.3 mmoles of H2O formed give 1412.11 J of heat
1mol= 1000mmol can give heat = [1000mmol /1mol] x1412.11J /25.3mmol
=55814.56 J
= 55.814 kJ/mol of H2O
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