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a. Draw the first propagation step for a bromide free radical and the double bond of...

a. Draw the first propagation step for a bromide free radical and the double bond of 1-methylcyclohexene. HINT: One electron from the double bond interacts with the bromide free radical to form a new bond. The other electron from the double bond attaches to one of the carbons. Be sure to use three single-headed arrows, and don't forget to draw the two possible free radical products that will form from this step. Circle the most likely product and explain why it is the major product.

b. Draw the reaction between the major free radical formed in the first propagation step with another equivalent of H-Br. Don't forget to use arrows. Your final product will be an alkyl halide and a bromide free radical.

c. Is the product Markovnikov or anti?

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