Question

For the system shown below, the difference between PA and Pg is 1100 Pa. Determine the SG of the liquid in the tank for a = 4.3 cm, b = 10 cm, and c = 3 cm. The specific weight of water is 9790 N/m3 SG = 0.8 Liquid, SG = ? 2 cm 10 cm Jom

Answer 1

Air B S403 0.03 m 0.m 0.07m Nale Note : @ At first, the unit conversion is done from cm to m by multiplying the number with 10-2 & while going upwards, sign es considered ove & while going downwards es considered a +ve. Acceleration due to 1. gravity Given: specific weight of water, Sw = 9790 4. - PA - PB = 1100 Pa = 1100 m Now, welting Pressure for the system Density of water Pa - Sw * (0.043 m) + (SG) * Sw * g *(c.im) - (sa*) x Sw x 9460.07+) ac elemente de esto = Ps. -> ln - ) - (9 290 ) » (0.093 yi) + (0.8) *(2000 m.) * (4.91 ) 10.1m) - (£«*) x (looo ) x 3-1 ) * (P.1 -) = 0 > (100 %) -(420.42 ) + 284.8 (9*X4) - (669) + (pa (Xb)] = 0

=> (867) * (981 ) = (100 %) - (480.92 t ) + (284.3 M) 5) (56) * (nie) = (1462.9 *) >> (540) = 1463.83. 1463. 981 Therefore, .SG* in the liquid tank is 1.49. AS