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Part A What is the moment of inertia of a uniform thin rod of mass 5 kg and length 0.6 m rotated about a point halfway betwee
Solve and explain verbally why.
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Solution Given M2 5kg L 0.6m 1 1 cm ² mL using formula parallel axis theorem Iz Im + md2 da L12 and a m L2 + MCL)2 12 4 1 2

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