Question

1. For the element shown y - 4 V and i = 10e-0.5 A fort 20. Find the energy supplied by the element between 1 and 3 seconds. 14,000 high-current batteries are connected in series. Each battery is rated at 12 V. If they can produce a jolt of 2.5 kA that lasts for 5 seconds, calculate the energy generated in kWh. EE 211 Exam 1/ Spring 2020 Page 1 of 6

Answer 1

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1. Given V=uv. and i cioé 0.5 i loe Atzo We know that time Energy - power x power =VI P = 4vx lict) dt. 3 ." -0.56 P = 4V x 10. 9 VX 10 P=4V X10 7 0.54 13 -051 녀 -0.5t p= -80 (eost) tal

PE=80 [2015 (8) 20:50 p=-s0 (0.2231 – 060657 P= -80(-0.5834] P = 300.672. W Energy = power & time Time = 3s-is. Time = 25 30.672 X Energy = | Energy = 61.344 J. The eneigy Supplied by the element between i and 3 Seconds is 61. 344 J.

Given 14,000 high-Current batteries are connected in Series Each battery is rated at 12v. in Series Voltages are added Total Voltage, V = 14,000 X 12V V =-168kv. is constant Current In Series I - 2.5 KA P.- VI D = 168K V X.215 KA P = 4204 w ... P = 420x106 w

Time egy = power X Given time = 5 sec Energy = 420x100 w x 5 sec ( Energy = 2100 x 100 ws ... energy in kwḥ th = 36005 is = 1 h 360 Ik w :=1000 w I (W. = 1kw 1000

Energy = 2100x100 + x1 kWh 1000 3600 Energy = 583.33 kwh/ Energy generated in Kwh is .:: 583.33 kwhi