Question

What is the cell voltage for chlor-alkali electrolysis of 64.35% NaCl (by weight), if the concentrations and partial gas pressures of the products are the following: 2.00 M NaOH, PcI2 = 2.00 atm, PH2 = 0.100 atm? 0 -3.5 0 -2.12 3.2 0 -3.8

Answer 1

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Reaction at cathode : 2H2O + 2e ==> 2OH- + H2

Reaction at anode : 2 Cl- ===> Cl2 (g) + 2e

Vcell = 3.2 V

ans. 3.2

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In electrolytic purification of Cu Anode is: Copper

(pure Cu - cathode ; impure Cu - Anode )