Question

Da POINTS 3/3 POINTS PREVIOUS ANSWERS PREVIOUS ANSWERS ASK YO A new liquid substance has been discovered that freezes at 25°C. A scientist poured the liquid (which was at 25°C) into a 0.678 kg cup (the cup was at -34°C) which caused som of the liquid to freeze (only 0.247 kg of the liquid froze). As a result, the cup gained 44,000) of heat until thermal equilibrium was reached. Determine the latent heat of the sub specific heat of the cup. L = 178137.652 J/kg Ccup 1099.945 /kg.K . ......T,= -34°C b) Q2 = M₂C (T2-T) T2= 25°C 44,000 = (0:678)C(25-(-34)) 0.678 XCx59 44,000 = 40.002 XC Te = 1,099.945 5/kgik 40.002

Please show me your work for L. I have the correct answer but i do not know how to get to it. Please explain. Thank you, I will rate.

Answer 1

BIT, GORAKHPUR Alin Given As the nature value of of phase hat latent change depend upon In our selid case, liquid changes from dig to this means the latent heat of raponsation Formula of bor Latent creat Where L = Latent heat M o= amount of heat M = mass of substance We han Freezing point of liquid Cup was at tempratwy = 25°C = -34°C logistat Mass of liquid which Mass of cup = 0.678kg freeze after addion in to cup at stemp 34°C = 0.247kg | The - heat of galnad liguld dy to cup ice drurg the 44000 7 conversion = solution ( Latent heat of substanco that con urted into soled ice from liquid IM/ 1440001 [0.247) guten o = that youn ty cup to i= mass of liaud conuested = 178137.6518I/kg conurt liquid into ice Into ice = 0.247169

BIT, OORAKHPUR calculation aprendic hot 0 = MCAT O amound dead award to charge and wo soud 99 000 M = mass that is converted from the above beat 0.' M = mass of the cup that cause the charge of liquid to sold ser T = stemp of cup = -29°c To = temp of liqued = 25°C о е мс. Дt O = Mc (T-TJ 44000 = 0.678 (35°C - (-34°C) xc 44 000 6.678 X ( 59°C) 44000 = ( 40.002 c= 1099.945003 e= specific hat og