Homework Answers
Bearing of line 1-2 = 48°30'
Bearing of line 1-A = 48°30' + 45° = 93°30'
Bearing of line A-1 = 180° +93°30' = 273° 30'
Coordinates of 1 = (1500' N , 1200' E)
Coordinates of 2 = (1665.65' N , 1387.238' E)
Coordinates of A = ( 1487.79'N ,1399.626'E )
Thus length 2-A = 178.29'
Thus 178.29/sin(45°) = 250/sin(A)
Thus A = 82°31'46.49"
Thus bearing of line A-2 = 273°30' + 82°31'46.49" = 356°1'46.49"
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