Question

Write the equilibrium-constant expression for the equilibrium Cs) + CO2(g) = 200) The table that follows shows the relative mole percent of CO2 and Code) at a total pressure of 1 atm for several temperatures. Calculate the value of Ke at each temperature. Is the reaction exothermic or endothermic? Temperature (°C) 850 950 1050 1250 CO2 (mol %) 6.23 1.32 0.37 0.06 co (mol %) 93.77 98.68 99.63 99.94

Answer 1

Equilibrium constanta Peo @ Bequilibrium constant » kpl cohere Pes a partial pressure. 1 cop o, pontial premice 423,8) At t= 850°C Peo - (1x 6,123) atm , 0.0623 atm Peo= (1x 93.77 ) atm - 0.9377 atm 100 kp- (0.9377)2 14.113 0.0623 At F=950e Peo= (1032/100) atma 0.0132atm/Peo= 0.9868 atm kp- (0.9868) = 73.770 000132 At Talo50°C (0.9063) Peo, = 0.0037 atm ; Peo? 0.996 zariade; kp? 0.0032 2 268.27 At T=1250C (0.gggu)? Peo = 0.0006 atm; Peo= 0.9ggu atm; kp1.000 = 1664.667 with increase in temperature increases so the reaction is the rate of the reaction endothermie in nature.