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3. Calculation (7 *8 = 56) (1). Disscuss the convergence of the series (n=1 sinzn .

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8. lim antt lim sie (ht im ( 17 ) Motos TT sin (m) lim 3+1 mo 30+1 TT sim (m) 30 TT 33 lim 3n+1 19 no cot 3n+1 lim sin ( 908Now, we see that, TT and 0 as no 2 3m 3nt1 And, we already know that, sina lim to sl. x sin ( So, lim 3n+ → 1 T n too gnt! siHence, we see that, lim jamt 1 = 1 2 : Ism() is absolutely, convergent, and hence convergent . n!

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3. Calculation (7' *8 = 56') (1). Disscuss the convergence of the series (n=1 sinzn .
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