Question

3. Use correct arrow formalism to show a bomolytic bond cleavage of ethane to produce two methyl radicals. 4 pts NH 66, hr CH

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Answer #1

31.

In the presence of light energy C - C bond gets cleaved homolytically, to give two methyl radicals.

The way you wrote is correct.

32.

The way of movement of pi electrons through homolytic cleavage to give the different resonance structure is correct.

33.

Addition of bromine radical to pi bond leads to more stabel tertiaru carbon free radical, that you have drawn is correct.

34.

The steps that do not involve in the formation of active radicals indicate the termination steps.

(c)

(d)

are the termination reactions.

Note: All your answers are correct.

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