A 1210-turn solenoid 29.2 cm long and 1.58 cm in diameter carries 165 mA.
How much magnetic energy does it contain?
Express your answer with the appropriate units.
energy in a solenoid = 1/2* L *I^2
L = u0 * n^2 * A/l = 1.2354 mH
so
energy = 1/2 * 1.2354 *10^-3 * 165 *10^-3
= 101.92 * 10^-6 J
A 1210-turn solenoid 29.2 cm long and 1.58 cm in diameter carries 165 mA. How much...
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