A compound contains 0.24 g C and 0.050 g H. The molar mass of the compound is 58 g/mole. What are the empirical and molecular formulas of the compound?
Element mass A.wt no of moles
C 0.24g 12 0.24/12 = 0.02moles
H 0.05g 1 0.05/1 = 0.05 moles
C : H = 0.02 : 0.05
= 0.02/0.02 : 0.05/0.02
= 1:2.5
= 2: 5
empirical formula = C2H5
molecular formula = (empirical formula)n
n = M.wt/E.F.Wt = 58/29 = 2
molecular formula = (C2H5)2 = C4H10
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