Question

JAVA CODING:

(14 points) Abstract Class exercise You are given two abstract classes with no abstract method in the NoGo.java file. The purpose of this exercise is to get familiar with abstract class and its object creation 4. Follow the steps below: (be sure common on each to score points) 1) 2) 3 points) Create a subclass Go1 with Nogo1 as its super class and create Go1() constructor 3) (2 points) Now inside the NoGo class create an instance of Go1, you should be able to run it. 4) (2 points) In Nogo2 class (abstract) add an abstract method as the following (2 points) Use the NoGo.java file to show that you cannot create any instances (reference variables) of these two classes that print a "Go1()" message What is the display? Please explain what happen abstract void nMethodl: 5 (2 points) Create a new class Go9 that extends the Nogo2 class and overrides the nMethod method. The constructor for Go9( displays " Go9()" (2 points) In Nogo2 class (abstract) add an abstract method as the following abstract void nMethod 6) Run NoGo program, You should see the following display:(1 points) NoGo1() Go1() Go9() get nMethod() out of abstraction

Answer 1

As NoGo1.java and No NoGo2.java was not given just created on the basic of requiremnt.
you can find the comment the section numberering in which explain the points from question.

//NoGo1.java

public abstract class NoGo1 {

    public NoGo1(){
        System.out.println("NoGo1()");
    }
}

//NoGo2.java
public abstract class NoGo2 {

    // 4. abstract method
    abstract void nMethod();
}


// Go1.java

// 3. Go1 class that extending NoGo1 abstract class
public class Go1 extends NoGo1 {

    public Go1(){
        super();
        System.out.println("Go1()");
    }
}


//Go9.java

// 5. Go9 that extending the NoGo2

public class Go9 extends NoGo2 {

    public Go9(){
        System.out.println("Go9()");
    }
    @Override
    void nMethod() {
        System.out.println("get nMethod() out of abstraction");
    }
}

//NoGo.java

public  class NoGo {


    public static void main(String[] args) {
       // 1) you cant create instance of abstract class
//        NoGo1 o1 = new NoGo1() ;
//        NoGo2 o2 = new NoGo2() ;
        // 3. creating the object of Go1 its constructor will call
        // NoGo1 class constructor and print NOGo1() first then
        // it will print Go1()
        Go1 obj = new Go1();
        Go9 obj1 = new Go9();
        obj1.nMethod();
    }
}


//OUTPUT
NoGo1()
Go1()
Go9()
get nMethod() out of abstraction