Question

A strip of invisible tape 0.13 m long by 0.011 m wide is charged uniformly with a total net charge of 4 nC nano 1 x 10-9 and is suspended horizontally, so it lies along the axis with its center at the origin, as shown in the figure below. Calculate the approximate electric field at location (0, 0.02, 0) m (location A) due to the strip of tape. Do this by dividing the strip into three equal sections, as shown in the figure below, and approximating each section as a point charge. (Assume each point charge is located at the center of the section it approximates. Express your answer in vector form.) (a) What is the approximate electric field at A due to piece 1? N/C (b) What is the approximate electric field at A due to piece 2? N/C (e) What is the approximate electric field at A due to piece 3? N/C (d) What is the approximate net electric field at A? Enet N/C (e) What could you do to improve the accuracy of your calculation? Use a larger charge for piece 2 than for pieces 1 and 3: since location A is closest to piece 2, this piece has the most significant contribution Use a smaller charge for piece 2 than for pieces 1 and 3: the actual electric field is similar to the field of a dipole, with most of the charge on the tape at the left and right ends Use just two sections: due to symmetry about the y-axis, the components of the fleld due to each charge will be half of the total electric field Use more sections: as the number of segments approaches infinity, the summation of the electric fields approximates the actual electric field. Additional Materials Section 152 A strip of invisible tape 0.13 m long by 0.011 m wide is charged uniformly with a total net charge of 4 nC (nano = 1 ✕ 10−9) and is suspended horizontally, so it lies along the x axis, with its center at the origin, as shown in the figure below. Calculate the approximate electric field at location 0, 0.02, 0 m (location A) due to the strip of tape. Do this by dividing the strip into three equal sections, as shown in the figure below, and approximating each section as a point charge. (Assume each point charge is located at the center of the section it approximates. Express your answer in vector form.)

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Soln a) X eo ordinale obu, e coed te %strip i.x: o.13 2- 6 a 433 m The Point at the eantne c( strip 4, c (-o.oy33)o)o) 2. 2bislanes belwou oulte o stsp 2 and point A, 0.02 m 2. 2. (o.02) c) Eleetsic ドed al abput Y- z pane (ee 15 + 205 )s:15 1 2051.

Add a comment
Know the answer?
Add Answer to:
A strip of invisible tape 0.13 m long by 0.011 m wide is charged uniformly with...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A strip of invisible tape 0.15 m long by 0.012 m wide is charged uniformly with...

    A strip of invisible tape 0.15 m long by 0.012 m wide is charged uniformly with a total net charge of 4 nC (nano = 1 times 10^-9) and is suspended horizontally, so it lies along the x axis, with its center at the origin, as shown in the figure below. Calculate the approximate electric field at location (0, 0.02, 0) m (location A) due to the strip of tape. Do this by dividing the strip into three equal sections,...

  • Problem 15.28 (Multistep) A strip O invisible tape 0.15 m ong by 0.017 m wide is...

    Problem 15.28 (Multistep) A strip O invisible tape 0.15 m ong by 0.017 m wide is charged uniformly with a total net charge of 5 nC nano = 1 x 10 9 and is suspended horizontally, so it lies along the x axis, with its center at the ongin, as shown in the gure below. Calculate the approximate electric field at location <0, o.07, 0> m (location A) due to the strip of tape. Do this by dividing the strip...

  • A strip of invisible tape 0.12 m long by 0.013 m wide is charged uniformly with...

    A strip of invisible tape 0.12 m long by 0.013 m wide is charged uniformly with a total net charge of 5 nC (nano = 1e-9) and is suspended horizontally, so it lies along the x axis, with its center at the origin, as shown in the diagram. Calculate the approximate electric field at location < 0, 0.03, 0 > m (location A) due to the strip of tape. Do this by dividing the strip into three equal sections, as...

  • Please answer in vector format! Thanks!! A strip of invisible tape 0.17 m long by 0.011...

    Please answer in vector format! Thanks!! A strip of invisible tape 0.17 m long by 0.011 m wide is charged uniformly with a total net charge of 4 nC (nano = 1 times 10^-9) and is suspended horizontally, so it lies along the x axis, with its center at the origin, as shown in the figure below. Calculate the approximate electric field at location (0, 0.09, 0) m (location A) due to the strip of tape. Do this by dividing...

  • Problem 15.28 (Multistep) A strip of invisible tape 0.15 m long by 0.017 m wide is...

    Problem 15.28 (Multistep) A strip of invisible tape 0.15 m long by 0.017 m wide is charged uniformly with a total net charge of 5 nC (nano 1 x10- and is suspended horizontally, so it lies along the axis, with its center at the origin, as shown in the figure below. Calculate the approximate electric field at location <0, 0.07, 0> m (location A) due to the strip of tape. Do this by dividing the strip into three equal sections,...

  • Electric field

    A strip of invisible tape 0.16 m long by 0.015 m wide is charged uniformly with a total net charge of 5 nC (nano = 1e-9) and is suspended horizontally, so it lies along the x axis, with its center at the origin, as shown in the diagram.Calculate the approximate electric field at location < 0, 0.03, 0 > m (location A) due to the strip of tape. Do this by dividing the strip into three equal sections, as shown in the diagram, and approximating each section as...

  • PLEASE PROVIDE SOLUTION IN VECTOR FORM AND SHOW ALL STEPS. THANK YOU! A plastic rod 1.8...

    PLEASE PROVIDE SOLUTION IN VECTOR FORM AND SHOW ALL STEPS. THANK YOU! A plastic rod 1.8 m long is rubbed all over with wool, and acquires a charge of -3e-08 coulombs. We choose the center of the rod to be the origin of our coordinate system, with the x-axis extending to the right, the y-axis extending up, and the z-axis out of the page. In order to calculate the electric field at location A0.7, 0, 0 > m, we divide...

  • Exercise 23.7 Hints: Getting Started | I'm Stuck A rod 12.5 cm long is uniformly charged...

    Exercise 23.7 Hints: Getting Started | I'm Stuck A rod 12.5 cm long is uniformly charged and has a total charge of -27.0 PC. (a) Determine the magnitude of the electric field along the axis of the rod at a point 31.0 cm from its center. E = 13433.80109 X N/C It might be helpful to carefully follow through the example to make sure you understand the solution. (b) Determine the direction of the electric field along the axis of...

  • 3. A uniformly charged ring of radius, a, below. The net charge is positive. The location...

    3. A uniformly charged ring of radius, a, below. The net charge is positive. The location A is in The location B is a distance, a, directly above above the center of the ring. zed ring of radius, a, is situated horizontally, as shown Tge is positive. The location A is in the center of the ring. is a distance, a, directly above the center. Location C is very far a. Starting with the definition of the electric field, E...

  • A long uniformly charged thread (linear charge density A -2.1 C/m) lies along the z axis in the figure.

    A long uniformly charged thread (linear charge density A -2.1 C/m) lies along the z axis in the figure.(Figure 1) A small charged sphere (Q =-2.4 C ) is at the point x=0 cm, y = -5.0 cm.Part AWhat is the direction of the electric field at the point x = 7.0 cm, y =7.0 cm? Ethread and EQ represent fields due to the long thread and the charge Q, respectively.Part B What is the magnitude of the electric field at...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT