PLEASE PROVIDE SOLUTION IN VECTOR FORM AND SHOW ALL STEPS. THANK YOU!
PLEASE PROVIDE SOLUTION IN VECTOR FORM AND SHOW ALL STEPS. THANK YOU! A plastic rod 1.8...
Please answer in vector format! Thanks!! A strip of invisible tape 0.17 m long by 0.011 m wide is charged uniformly with a total net charge of 4 nC (nano = 1 times 10^-9) and is suspended horizontally, so it lies along the x axis, with its center at the origin, as shown in the figure below. Calculate the approximate electric field at location (0, 0.09, 0) m (location A) due to the strip of tape. Do this by dividing...
A strip of invisible tape 0.13 m long by 0.011 m wide is charged uniformly with a total net charge of 4 nC (nano = 1 ✕ 10−9) and is suspended horizontally, so it lies along the x axis, with its center at the origin, as shown in the figure below. Calculate the approximate electric field at location 0, 0.02, 0 m (location A) due to the strip of tape. Do this by dividing the strip into three equal sections,...
A strip of invisible tape 0.15 m long by 0.012 m wide is charged uniformly with a total net charge of 4 nC (nano = 1 times 10^-9) and is suspended horizontally, so it lies along the x axis, with its center at the origin, as shown in the figure below. Calculate the approximate electric field at location (0, 0.02, 0) m (location A) due to the strip of tape. Do this by dividing the strip into three equal sections,...
Problem 15.28 (Multistep) A strip O invisible tape 0.15 m ong by 0.017 m wide is charged uniformly with a total net charge of 5 nC nano = 1 x 10 9 and is suspended horizontally, so it lies along the x axis, with its center at the ongin, as shown in the gure below. Calculate the approximate electric field at location <0, o.07, 0> m (location A) due to the strip of tape. Do this by dividing the strip...
A strip of invisible tape 0.12 m long by 0.013 m wide is charged uniformly with a total net charge of 5 nC (nano = 1e-9) and is suspended horizontally, so it lies along the x axis, with its center at the origin, as shown in the diagram. Calculate the approximate electric field at location < 0, 0.03, 0 > m (location A) due to the strip of tape. Do this by dividing the strip into three equal sections, as...
Show derivation steps from equation (22-16) to (22-17) please show steps. Thank you. the quantity s varies as we go through the eleme, remain the same, so we move them outside the integral. We find (22-15) 2rR 22-16) If the charge on the ring is negative, instead of positive as we have assumed, the This is a fine answer, but we can also switch to the total charge by using A-q (charged ring). magnitude of the field at P is...
A thin rod lies on the x-asix with one end at -A and the other end at A, as shown in the diagram. A charge of -Q is spread uniformly over the surface of the rod. We want to set up an integral to find the electric field at location <0, y, 0> due to the rod. Following the procedure discussed in the textbook, we have cut up the rod into small segments, each of which can be considered as...
A wire through which a current is flowing lies along the x-ais as shown. Connecting wires which are not shown the diagram connect the ends of the wire to batteries (which are also not shown). Electron current flows through the wire in the -x direction, as indicated in the diagram. To calculate the magnetic field at location A due to the current in the wire, we divide the wire into pieces, approximate each piece as a point charge moving in...
Problem 15.28 (Multistep) A strip of invisible tape 0.15 m long by 0.017 m wide is charged uniformly with a total net charge of 5 nC (nano 1 x10- and is suspended horizontally, so it lies along the axis, with its center at the origin, as shown in the figure below. Calculate the approximate electric field at location <0, 0.07, 0> m (location A) due to the strip of tape. Do this by dividing the strip into three equal sections,...