1)
as concentration of HI is very low we have to consider the H+ from water also
[H+]total = [H+]HI + [H+]H2O
[H+]total = 8.3 x 10-8 + 1.01 x 10-7
[H+]total = 0.83 x 10-7 + 1.01 x 10-7
[H+]total = 10-7 (0.83 + 1.01)
[H+]total = 10-7 (1.84)
pH = -log [H+]
pH = -log [1.84 x 10-7]
pH = 6.74
2) [H+]H2O = 1.01 x 10-7 M
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From narrow range pH values. Use [H^+] = 10^-pH; **Use K_w = [H^+][OH] = 1.0 times 10^-14
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