a) the mean =56.32
the median =55.37
b)variance =379.78
standard deviation =19.49
range =85.55
Coefficient of variation =(std deviation/mean)*100 =(19.49/56.32)*100 =34.61% (try 34.60% if this comes wrong)
c)
yes the data are right skewed
d)
the average amount spent is 56.32 and half the customer spent more than 55.37 . the average scatter,,,,,mean is 19.49 . The difference between...........spent is 85.55
A-D pleasees 02:44:25 Submit Quiz Quiz: Final Exam Time This Quiz: 50 pts possible 14 of...
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