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For the capacitor circuit show below, the potentia

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Answer #1

4and 4 are series

effective capacity is 2microF

2 and 2 are in parallel so effective capacity is 4microF

4 and 2 are in parallel so effective capacity is 6microF

3and 3 are in parallel so effective capacity is 6microF

6and 6 are in series so effective capacity is 3microF

hence a) eq capacity between A and B is =3micro Farad.

b) the total charge will be divided into 2 equal parts it is=3microFX120 (120V was given in the problem)=360microC

in the upper part chaarge is =180micro C again this will be divided into 3 equal parts

so the charge that stored in the 4 micro F capacitors=60micro C

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