Question

A cannonball is fired horizontally from the top of a cit. The cannon is at height = 600 m above ground level and the ball is fired with initial horizontal speed to. Assume acceleration due to gravity to be 9 9.80 m/s - Part A . What is the position of the Assume that the cannon is fired at time t = 0 and that the cannonball hits the ground at time cannonball the time 27 Answer numerically in units of meters. View Available Hint(e) O AEROR? Submit Part B Given that the projectile lands at a distance D. 190 m from the cit as shown in the figure, find the initial speed of the projecte Express the initial speed numerically in meters per second View Available Hints) 0 AEO ROB? Submit Part What is the position of the cannonball when is al distance D/2 from the equation for this projectile, which gives y in terms of directly you need to you can use the trajectory y You should already know thx from the previous part Express the position of the cannonball numerically in meters PAEDROO? Request Answer

Answer 1

SWI 2x bo 3.499 sec H: 6.my on Taking motion alony Horizontal dincendion - D= Untg on Toring motion elong vesticle disection 1. HE t gtg ty: 624. lex ebony = 3.499 sec past A. y (19/2) = £9 (22) 2 = **9.80 97479)15m 9.9 Part B from eq (1) C D = lotg 190 5%297 mis .499 : prt s. ahen m mysat 1.75m