Question

2. For the circuit shown below, the resistance values are R1 = 512, R2 = 101, R3 = 1522, R4 = 2012 , R5 = 2522, R6 = 3032, R7 = 3512, and Rg = 4012 (in short, Rn = n x 52). Determine the Norton equivalent between the terminals a and b. Ro i 18A R} } R 10 V

V1= 8V @node above R1

V2=4.64V @node between R6 and R7

V3=16.96V @node between R7 and R8

Answer 1

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en corecut come and value of Resistance en norsk gineu R2 18А a 46 ay orton equivalent between for Morton equival &RN of a fb tereunal circuited so value of IN and find current short as Rus 8V JA O FR ane source Realue cuneet to voltage Jones transformation, PS1 = JA 4ov 7 w and v=1 10.9.2 Valu R= R311 lor noris & 10.92 B WXS 2.16 volt! Y-

Reduced circuit Redue so O g. 10 vot you apply kel at Modeli 1, +47 +12 + 13-0 al,-40 & u Ixt yiove to RI L-uo + uve t(1, -V2) ( 1 + ) = 0 (N-VI) (1 + 20 R2 Ri u, -40 + u ve 4V, X 1200,- 40) + Un612 + (1,-) (342) = 0 124 - 480+ 2 ure + Svi- 5V2 = 0 170, +1982 = 480 apply KCL af pode ve - 1 tlu -I3 tint is = 0 (W-X do +40) (-5) 5) + V2 - (2) (34) + (22-03) / Go + 2 = 0 875) lo () - 1600 cons -

apply KCL at noch va - ulx - sy is + Iso - u 2 + 3-12 + Vzove & Ng-2010 o - uve + (Ug-xz) (1/2 + 1/35 ) + (13-248) = 0 10-9 - V2 (+995) (as tong) og some 0, ① and ① V = 9.39 voll, and get the Valley Vo = 16-88val, Ig - 50.53 volt 9.39 - 96-06 - -0.3735A do 12 - -1.3468 A - U2 - V3 16.6 - 50.53 25 Iu= Rs at A apply KCL again IN 14 12 IN= 0.973 A IN - 1.3468 -0.3731= Replay RN Tu melepepenolent current soluce open circutorial independleurt voltage sowce short circuit find Rab parallel Roi 0 0 ER

Redonos Thy - Rab - Join Rz & Rz 11 le & vi-va tui, o apply kel at +V, -b wy, Noua - u vb zo Ru wit - 26 RI =0 ~ + Virub & vina + 4b T 30 IRM, - 2V - 2 Vyt 34, -380 + 24 Vo=0 13v1 - 3Va +22 = 0 apply kel at Node. + + b 2 = 0 Wn Pr Vory RG btt 3 + 2) + 1150 - 15 v (20) - 35 35 201240

apply ke at Node - I + a Va - Uz vare fu va ( 176 ) - 25 0 - va () - 30 25 m Node RCL at u apply & . + U2 - B Rz Pollo R2 & ve- Rr -uin 1 (-) + (*) and Low cl will Knored that v = Va-V G 7 and 8 solve by using equadras W, 5 get the value of 1RM = 1/2 as given the value of nl as V = not I x5 = 9.3 9 volt. for U2 = N2 = R2 [x = 16.86 vort

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