Sample proportion = 0.46
Sample standard error = SQRT(0.46 x (1 - 0.46)/50) = 0.07
Z-value for 95% CI = 1.96
So, margin of error = 1.96 x 0.07 = 0.137
So, the 95% limit for the population proportion of voters who will
vote for the candidate: (0.46 - 0.137 , 0.46 + 0.137) = (0.323 ,
0.597)
#13 13) A random sample of 50 voters found that 46% were going to vote for...
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