a)
Test statistic,
z = (pcap - p)/sqrt(p*(1-p)/n)
z = (0.5143 - 0.5)/sqrt(0.5*(1-0.5)/1400)
z = 1.07
b)
if z =1.28
p value = 0.1003
(20 points) A random sample of n = 1400 registered voters and found that 720 would vote for the Republican candidate in...
A random sample of ?=1400 registered voters and found that 720 would vote for the Republican candidate in a state senate race. Let ? represent the proportion of registered voters who would vote for the Republican candidate. Consider testing ?0:?=.50 ??:?>.50 a) the test statistic is z = ? b) Regardless of what you actually computed, suppose your answer to part (a) was z = 1.28. Using this z, p-value =?
(4 points) A newspaper conducted a statewide survey concerning the 1998 race for state senator. The newspaper took a SRS of n = 1400 registered voters and found that 720 would vote for the Republican candidate. Let p represent the proportion of registered voters in the state who would vote for the Republican candidate. We test Ho: p= .50 H:p>.50 (a) What is the z-statistic for this test? (b) What is the P-value of the test? (6 points) A new...
In a random sample of 100 registered voters, 20 say they plan to vote for Candidate A.Determine a 95% confidence interval for the proportion of all the registered voters who will vote for Candidate A.You are interested in knowing support for candidate by gender to provide strategic advice to candidate B. Suppose your guess based on previous knowledge is that female support for candidate B is around 20 percent, and male support for candidate B is around 50 percent. Suppose...
(4 points) A newspaper conducted a statewide survey concerning the 1998 race for state senator. The newspaper took a SRS of n = 1400 registered voters and found that 720 would vote for the Republican candidate. Let p represent the proportion of registered voters in the state who would vote for the Republican candidate. We test Hop=.50 H.:P > .50 (a) What is the 2-statistic for this test? (b) What is the P-value of the test? (6 points) A new...
In a random sample of 400 registrered voters, 120 indicated they plan to vote for Candidate A. Determine a 95% confidence interval for the proportion of all the registered voters who will vote for Candidate A.
#13 13) A random sample of 50 voters found that 46% were going to vote for a certain 13 candidate. Find the 95% limit for the population proportion of voters who will vote for that candidate.
9. A random sample of 80 voters found that 38% were going to vote for a certain candidate. Find the 90% limit for the population proportion of voters who will vote for that candidate. A) 29.0% <p < 47.0% B) 30.0% <p < 46.0% C) 31.1% <p < 44.9% D) 33.5% <p < 42.5%
A random sample of 60 voters found that 42% were going to vote for a certain candidate. Find the 99% limit for the population proportion of voters who will vote for that candidate.
(a) A newspaper conducted a statewide survey concerning the 1998 race for state senator. The newspaper took a SRS of 1200 registered voters and found that 620 would vote for the Republican candidate. Let p represent the proportion of registered voters in the state who would vote for the Republican candidate. A 90 percent confidence interval for p is: A. 0.517 t0.024 B. 0.517 ± 0.014 C. 0.517 ± 0.249 D. 0.517 +0.028 (b) A newspaper conducted a statewide survey...
A random sample of ikely voters showed that 64 % planned to vote for Candidate X, with a margin of eror of 1 percentage points and with 95 % confidence, a. Use a carefully worded sentence to report the 95 % confidence interval for the percentage of voters who plan to vote for Candidate X b. Is there evidence that Candidate X could lose? c. Suppose the survey was taken on the streets of a particular city and the candidate...