Question

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Solve the equation by making an appropriate substitution. 14) (x2 - 2x) - 23x2 - 2x)+ 120 - 0 answer {-3, -2, 5,4} Solve the radical equation, and check all proposed solutions. 15) V6x + 16 - answer {8}

Answer 1

And : 14). (x²-2x) * - 23 (x - 2x) +120=0 Let x2-2x= u 5o u² - 23 ut 1200 u²-84-15 u + 1200 u(4-8) -15 (4- 8) = 0 50 (4-15) (4-8)=0 so, u=15, u= 8 Now, y o upu

(a) when u= 15 22 - 2x - 15-0 2- 52+ 3x-15-0 (2-5) +3(2-5)=0 2=5, - -3 (6) when u= 8 22-22-8-0 x² 40+2x-850 (2-4) + 2(x-4)=0 (-4) (2+2) = 0 = 4, x=-2 - (-3,-2,5,4% 5). And i here, 16x tb = x 50 E Taking saraleon o sides 6x +16= x² x² - 6x -16=0 x ² - 8x + 2x-16=0 x(x-8) + 2(x-8) = 0 x = 8, x=-2 By ( ) Ext-2 x= {8}