A solenoid carries a current of 9.2A and has a coil density of 977turns/cm. What is the magnitude of the magnetic field near the middle of the solenoid? (mT, three significant figures)
the magnetic field near the middle of the solenoid
B = uo*n*I
n = number of turns per unit length = 977 turns/ cm = 97700 turns /
m
I = current through the solenoid
uo = magnetic permeability of the free space = 4*pi*10^-7
B = 4*3.14*10^-7*97700*9.2
B = 1128.9 mT
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