a)
here margin of error E = | 0.03 | |
for90% CI crtiical Z = | 1.6449 | |
estimated proportion=p= | 0.500 | |
required sample size n = | p*(1-p)*(z/E)2= | 752.00 |
( please try n=748 if above comes wrong due to rounding error)
b)
here margin of error E = | 0.03 | |
for90% CI crtiical Z = | 1.6449 | |
estimated proportion=p= | 0.440 | |
required sample size n = | p*(1-p)*(z/E)2= | 741.00 |
( please try n=737 if above comes wrong due to rounding error)
c) having an estimate reduces sample size requirement)
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