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A researcher wishes to estimate, with 99% confidence, the population proportion of adults who support labeling legislation fo

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Answer #1

(a)

Proportion = p = 0.5 Margin of Error = E = 0.06 Confidence Level = 99 Significance Level = Q = (100-99)% = 0.01 a/2 = (0.01/2

(b)

Proportion = p = 0.83 Margin of Error = E = 0.06 Confidence Level = 99 Significance Level = a = (100-99)% = 0.01 a/2 = (0.01/

(c) Having prior study, decreases the sample size.

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