Question

3. Write the electron dot structures for COCI: (phosgene gas), C:H: (acetylene), PCls (phosphoroes trichloride), NO: (nitrite anion), and BH (borohydride anion). Use the elements column mumbers to determine the number of valence electrons needed for the dot structures. H is in column I-A. B is in column III-A. C is in column IV-A, P and N are in column V-A. O is in column VI-A. and CI is in column VII-A. All of the atoms, except for H, follow the octet rule. Once you have drawn the dot structures, label all of the double and triple bonds. Then, use the table below to determine the molecular shapes and bond angles. (25 pts) Bond Angle Atoms Connected to Central Atom Nonbonding Sum Shape Pairs 109.5 109.5 109.5 120 4 tetrahedral 4 trigonal pyramidal bent 4 2 4 triangular planar linear 3 2 180 2

Answer 1

Sum of number of bonds and lone pair is corresponding valence electrons.

A.C.C is atoms connected to central atom

and N.bp is non- bonding pairs

eliofren eelumn num ber CVE)Valence Gdven V E n 4, VE- fn H 1, V E in B =3 V-G in PN = 5, v.E- m O z 6, V-E n l7 Eliotren det afnecture os Lewis det Btneture C4 CQ- D Co doubl bond 7 Sirgle bond atoms comecteol to Central atems (A.CC.) 3 Ca, ce,o) вugриоя иеи So gum 3to 23, Ao Jrazeal plarar Patrs (lone-palrs) -0 Shape bond angte = /20 C47v bond gfnge bple bond H HC genf HCECH H-cCH Pafrs (N-bp) O A-Cc. = 2 CCH) 0 and nen-bendlf Here So shape Mnear So Bum 2+0 = 2 and bond angle z180 CO P5 -4lone patri N-bp) So A-CC 3 (U,a,u), N-bp = 1 C2 me electens S Sum 3t -4 , Shape tigenal dPyramidal and bond angl Scanned with CAmScanner log-5

NO2 1) charga el give one clactoon ex tr O= N o So A C.c= 2 (0,0), Nbp Sum 2+1 3 Sohape Vhape bent A bond angle <18o 120° (6 BHA H-B-H H B So &um 4to A N bp 4 CH, AC-C ghape- tetoohedral and bend angle = /03.50 CS Scanned with CamScanner