Given rate,r=K[AB[^2
So order of the reaction is 2
For a second order reaction (1/A) = (1/Ao)+ kt
Where
Ao = initial concentration = 1.50 M
A = concentration left after time t = Ao/3 = 0.5 M
t = time taken = ?
k = rate constant = 0.70 L/mol-s
Plug the values we get t= 1.9~ 2s
It's not 7. Please help me solve! (: Thank you in advance! 1 attempts let Check...
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