Question

help plz need explanation too, thank you:)

1 attempts left Check my work Enter your answer in the provided box. A buffer that contains 0.416 M base, B, and 0.319 M of its conjugate acid, BH, has a pH of 8.98. What is the pH after 0.0020 mol of HCl is added to 0.250 L of this solution? pH- 9.19

Answer 1

conc. of Hul: ma = 0.002 = 0.00PM 0.25 volume For Basic Butter, ph 8.98 pon - 5.02 pon pky + log salt base 0.319 p 5.02= pth & log on 0.496 por = 5:02 = + 5.02= pkb + log 0.77 (-0.11) Toko = 5.13 Add strong acid in of weak acid decrease It We conc. basic and butter conc. then, of salt increa = 5-13 + pon - log 0.319 +0.008 6.416-0.008 picy & Log saltfx Base-x = 5-13 + log 0.327 0.008 - 5.13+ log (68) = 5.13+ (-0.050 - 5.03 ph+pon - 14 =1463834 pon - 14 - 5.03 = 8.97 roon 8.97