Volume of the laboratory = 12ft × 15ft × 8.50ft = 1530 ft^3 .
1 ft^3 = 28316.85 cm^3
Therefore 1530 ft^3 = (28316.85cm^3/1ft^3)×1530ft^3 = 43324780.5 cm^3 .
Hence volume of air in the room = 43324780.5 cm^3 .
Density of air = 0.00118 g/cm^3 .
Thus mass of air in the room = volume × density
= 43324780.5 cm^3 × 0.00118g/cm^3
= 51123.241 g × (1kg/1000g) = 51.123 kg air .
So mass of air in the laboratory room = 51.123 kg
Lethal dose of HCN = 300mg/1kg air
Then lethal dose in 51.123 kg will be = (300mg-HCN/1kg-air)×51.123kg-air = 15336.9 mg HCN = 15.3g HCN .
Thus amount of HCN which is lethal dose for this laboratory room is 15.3 g .
please box the answer and units <CH 04 HW 60f9 Hydrogen Cyanide Poisoning Constants Periodic Table...
Hydrogen Cyanide Poisoning Part A Calculate the amount of HCN that gives the lethal dose in a small laboratory room measuring 12.0 ftx 15.0 ft × 960ft. Hydrogen cyanide, HCN, is a poisonous gas. The ethal dose is approximately 300. mg kilogram of air when inhaled. The density of air at 26。C is 0.00118 g/cm" per Express your answer to three significant figures and include the appropriate units. Hints Value Units
Hydrogen cyanide, HCN, is a poisonous gas. The lethal dose is approximately 300. mg HCN per kilogram of air when inhaled. The density of air at26 C is 0.00118 g/cm3 Part A Calculate the amount of HCN that gives the lethal dose in a small laboratory room measuring 12.0 ftx 15.0 ftx9.70t Express your answer to three significant figures and include the appropriate units. Part B Consider the formation of HCN by the reaction of NaCN (sodium cyanide) with an...