Question

A rod system consists of two parts of steel A36 that are connected to pins. Each part has a cross section of 1000 mm². Determine how large the force P must be to move point A down 0.625 mm. (E = 200 GPa)
Answer: P = 213.3 kN

0,6 m -0,45 m-te-0,45 m-

0 0
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Answer #1

i at point A. Far Sino 10.6m. Ld2 - Facisino 0 45m. 0 45 tom o = 0.6 036870 FAB co .. X FAC Y FACCESO - FABLES Efx0(++) Fac se from Right angres AA”AS, - SAB AA19 Coso = AA - 2134375X109. p. Con 36.87 = = (0.625*10-3) P: 213333.04 A *Pa 213. 333 KN I

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