Question

In a certain region, the magnetic field is represented by the equation B = (a + bt)ſ, where a = 3.50 mt and b = 4.30 mT/s. A circular coil of area 1.90 x 10-3 m2 and N = 5 turns is oriented in the x-z (horizontal) plane in this field region. Due to the change in magnetic flux, charge passes by a given point in the circuit at a rate of 6.45 mc/s. Determine the resistance of the coil. m2

Answer 1

Ginen B = (a+bt)) at a= 93.5 MT = 3.5x585 b= 4-3 MT/s = 4-3x107/s à = 1990x533 | for Ar plane N=5 (direction of A is Alongs 9 ) i= da = 6:45 mc/s = 6.45x103 45 := 6.45X103A ( Rate of charge flow is called current) Indued emt E = - 48 - - BA F-N d (BA) BITA It E-NA dB (* A is constat dt = -NA debt) E-NAB = - 5x1.9 Xio?x4-3X163 =-40.25 X156 Magnitude JE 1 = 40858155 volt using - TE=iR R=151- 4.005 Nos i bus x163 R = 0.633 X15? de 6.33 X15? R=6.33 mm