Question

I T ILL 3: A motorcycle begins at rest at t=0 seconds. The motorcycle starts moving, and eventually covers a distance d=880 m, in a time = 108 s. In a coordinate system with north being the positive x-direction, the motorcycle's motion is in the northern direction (see figure). V south(-x) north(x) time, 60 Otheexpertta.com 25% Part() What was the motorcycle's average speed, ve, during this period, in meters per second? A 25% Part (b) What was the motorcycle's displacement in the northern direction during this period, in meters? A 25% Part (C) What was the motorcycle's average velocity in in the northern direction V N, in this period in meters per second? A 25% Part (d) If the motorcycle's final velocity at ty was 12 m/s, what was the motorcycle's average acceleration in the northern direction, 4avg.N, during this period in m/s2? Grade Summary Deductions Potential 100% wave NE

Answer 1

Solution Part @ Average speed = Total Distance Total time taken . 88.0 108 m sec Average Speed = 8.15 mils

Part 6 Since the matorcycle is moving toward Es north direction. - It's displacement towards north ů the total distance that it covered in the narth direction. - Clearly: Tit's Displacement = 880 meter S T: towards north

Part© Average Velocity in North Direction - -is one total chis placement in north direction divided by the tatal change in time Average. Velocillin Northe Direction - - Displacement in North Direction change in time m/s . . = 880 . 108 Haverage. Velocity=_8...15 . ms

resz Part @ 3+ Since Motor Cycle starts from Hits initial velocity, U = 0 ms. given, final velocity = 12 m/s change in time (tis- to) = 108 seco cceleration have.nl = (V-u) (tf-to) Average. Acceleration, Qarg. N = hoe _m/s2 Average Acceleration ; Carg, n = 0.1111 m/s2 108. T. UM-
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