Question

3. The following data are for the hydrogenation of benzene (reaction shown below). C6H60g) 3 H20g) 2 C6H12 (cyclohexane, g) T(K) Kp (atm) 298 1.43E +17 300 8.53E+16 400 7.06E+07 500 1.85E+02 600 3.05E-02. 700 5.66E-05 800 494E-07 900 1.23E-08 1000 6.49E-10 http://nvlpubs.nist.gov/nistpubs ires/37/jresv37n5p263 Alb.pdf Determine ArHo and Arso for this reaction.

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Answer #1

plot lnKp vs 1/T

slope = -dHo/R

intercept = dSo/R

slope from graph = -8.2402

dHo = -(8.2402 x 8.314) = 68.51 J

intercept from graph = 45.047

dSo = 45.047 x 8.314 = 374.521 J/K

Data points

1/T lnKp
0.003356 39.502
0.003333 38.985
0.0025 18.072
0.002 5.22
0.00167 -3.49
0.00143 -9.78
0.00125 -14.52
0.00111 -18.214
0.001 -21.155

Plot

Plot 60 yー-8.2402x+45.047 R2-0.9262 a 20 -+-Series! Linear (Series1) -20 -40 Lo 1/T (K-1)

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The following data are for the hydrogenation of benzene (reaction shown below). C_6H_6(g) + 3 H_2(g)...
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