Question

I am having a little trouble with these three. If you could explain how you solved them that would be wonderful. Thanks for your time.

Solve. cos2x + 1 = 2 cos x, 0<x< 211

Solve the triangle. a = 20, b = 8, C = 10

Solve the triangle. a = 30, b = 19,c= 41

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Answer #1

o cos²x+1=2cosu cos²x tl2cosn=0 (cost-1)2 = 0 -> cost-1=0 cosH = 1 Cost = coso - = 207 (8= 0. Cora (21)2 a= 20, b= 8, c=10 In given triangle is not valid triangle inequality, btosa But loir 20 (3 a=30, b=19, c=41 Using Cosine Ru

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