Question

6.5.4 a>0 Sketch the phase portrait for the system x = ax-x, for a < 0, a = 0, and

Could someone explain how these to get these phase portraits by hand with ẋ=y and ẏ=ax-x^2 especially for a=0 case where you have eigenvalues all equal to zero?

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Answer #1

When eigen values are zero then lambda = 0 , When x = y , y = ax - x^2

When a=0 , all these are converging towards zero and from there onwards it is diverging.

When a<0 , all these are converging towards zero in circular form and then it is diverging.

When a> 0 , all these are converging towards zero in nodal form and then it is diverging  

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