Determine the ultimate BOD (BODu) and 5-day BOD (BOD5) given that the BOD4 of a waste is 130 mg/L and K is 0.075 d-1 . Use yt=Lo(1-e-kt) and k=2.303(K).
Determine the ultimate BOD (BODu) and 5-day BOD (BOD5) given that the BOD4 of a waste...
Calculate the BOD Ultimate value given the following information BOD5= 316 mg/L k = 0.23 day-1 Temperature is 20 C for both BOD5 and BOD Ultimate (L)
1. (30 points) Determine the 1-day BOD (BOD) and ultimate CBOD (BOD, or Lo) for a wastewater whose 5-day BOD at 20 °C is 200 mg/L, when -0.23 day.
QUESTION 5 5.1 Determine the 4-day BOD and the Ultimate BOD (1st stage) for a wastewater whose BODs at 20 °C is 250 mg/l. The reaction constant is k=0.23d" (base e). Determine the BODs if the test had been done at 25 °C. (10) 5.2. The chlorination unit in a WWTP uses 10 containers of chlorine on a monthly basis. A chlorine dosage is 4 mg/l is used to treat an average monthly wastewater effluent of 500 000 mDetermine the...
(20 pts) The ultimate BOD of a domestic wastewater is 275 mg/L and the e based rate constant k=0.24 d a. (4 pts) What will be the 5-day BOD (Sample-1)? b. (4 pts) What will be the 7-day BOD? (Sample-1)? c. (4 pts) A different sample has the same ultimate BOD given in the question, but the 20 °C k value (e based) is equal to 0.36 dl Determine the 5-day BOD of this sample (Sample-2). d. (8 pts) Please...
O The town of Gangnam in Seoul, Korea discharges 17360 m3/day of treated wastewater in the Han River. The treated wastewater has a BOD5 of 12 mg/L and a BOD decay constant, k, of 0.12 day at 20 °C. The river has a flow rate of 0.43 m/s and an ultimate BOD, Lo, of 5 mg/L. The DO of the river is 6.5 mg/L and the D0 of the wastewater is 1.0 mg/L (a) Calculate the ultimate BOD of the...
QUESTION 1 6 point City of Hope's Wastewater has a ultimate carbonaceous BOD of 300 mg/L at 20 oC. The reaction rate k at that temperature has been determined to be 0.2/day. a) Find the BOD5. b)Find the reaction rate coefficient at 15 oC. c) Find BOD5 at 15 oC. O 132 mg/L, 0.18/day, 265 mg/L O 190 mg/L, 0.16/day, 165 mg/L O90 mg/L, 0.16/day, 245 mg/L O 232 mg/L, 0.18/day, 365 mg/L
You have collected water samples of the influent (raw sewage) and effluent (treated sewage) at Houston Wastewater Treatment Plant. You plan to conduct the BOD5 test to determine the BOD rate constant, k. A. Would you expect the rate constants to be the same or different in these two samples? If different, which would be higher and why? B. If the BOD5 for the raw sewage sample is 600 mg/L, and the ultimate BOD is 650 mg/L at 20oC, find...
(20)1. A wastewater has a BOD5 of 192 mg/L, a reaction rate k of 0.12/day, and a total Kjeldahl nitrogen content (TKN) of 35 mg/L. (a) (b) Find the ultimate carbonaceous oxygen demand (CBOD). Find the ultimate nitrogenous oxygen demand (NBOD). Find the total ultimate (or theoretical) oxygen demand (TBOD). Find the remaining BOD (nitrogenous plus carbonaceous) after five days have elapsed.
(a)The 5-day BOD of a sewage sample is 180 mg/L at 15°C. What is the BODu when k is 0.52 d-1 at 25°C? (use the Arrhenius equation, kt2=kt1?t2-t1 where ?=1.135 for 4-20°C and 1.056 for 20 -30°C (b)Graph the BOD as a function of time for the previous problem for both 15°C and 25°C. What do you observe?
Because of a holiday schedule, your lab neglects to measure a BOD test at t=5 days. But eventually measures the bottles at t=7 days, and gets a BOD7 = 211 mg/L. If the BOD rate constant is 0.201 day-1, determine the BOD5 of the waste.