Question

Knowing that the tension in cable AC of the system is 400 N, determine the magnitude of the force P. (Round the final answer to two decimal places.)

Knowing that the tension in cable AC of the system is 400 N, determine the weight W of the container. (Round the final answer to two decimal places.)

A container of weight Wis suspended from ring A, to which cables AC and AE are attached. A force P is applied to the end Fof a third cable that passes over a pulley at Band through ring A and that is attached to a support at D 0.40 m 0.86 m 1.20 m 1.30 m C 0.78 m P 0.40 m 1.60 m W

Answer 1

A (o, -1-6, 0) Position vector BC-0t8, 0 o) A -o78 JAB tot8) + (62 JAS 8t. TAB TAB CI) + 16 AC --A 2J +1.2 k JAC (16)2 + (12) 2 JAC 2 JAC TAC + 1-2 k 9-(2) 2 AD D= (.3, 0 D-A to4K +1.6 1.3 + O4k AD = 2 1 ADI TAD 6 34 +0.44 AD C3 2-1

F-A F(-0-4, O AE 98-0 -O 86 k -044 6 LAE 98. (4) TAE JAE -O.42 . : 198 0 (S Eq EF +JAC + AD +TAE TAB A Ea. CI)-CSs components OF TAE (-0 4) JAB (-018) JAD (.3 2.I 98-1 Pullet SYStern JAD TAB ea be comes Above +TAE(-0. 4 P 2 1 J8 98.1 AE d 8081-0 O.21s TA) Ea

Components Eq.(D to (r) 1-6 -4) TAB TAC TAD 178 2.1 JAE -h TAC -400 N NOW TAB JAD P ВЬove Eq becomes 9-10 +400 2 1 2. +TAE -W 98.1 O.8602 TAE + 320 -W R o.8602 TAE 32o -W B Fa

componentS Eq (D-(3) +TAE -0.o 1-86 JAD 4 2 1 400 N TAC TAD P Above becomes 240 O4624 AF 240 4624 AE O1905 P TAE Three Unknonns (B) CC tThree equations Eq(A) Solving Eq s (A),(B) CC) get We P 1211 JAE JO18 320t LI