Form a 95% confidence interval on the difference in the means.
sample A B
sample size 10 10
sample mean 65.5 50.5
sample std dev 9 9
Form a 95% confidence interval on the difference in the means. sample A B sample size...
Find the 95% confidence interval for the difference between two means based on this information about two samples. Assume independent samples from normal populations. (Use conservative degrees of freedom.) (Give your answers correct to two decimal places.) Sample Number Mean Std. Dev. 1 10 34 27 2 21 22 31 Lower Limit Upper Limit
Find the 95% confidence interval for the difference between two means based on this information about two samples. Assume independent samples from normal populations. (Use conservative degrees of freedom.) (Give your answers correct to two decimal places.) Sample - Number - Mean - Std. Dev. 1 - 25 - 36 - 20 2 - 30 - 26 - 21 Lower Limit = Upper Limit =
Explain what "95% confidence" means in a 95% confidence interval. What does "95% confidence" mean in a 95% confidence interval? A. If 100 different confidence intervals are constructed, each based on a different sample of size n from the same population, then we expect 95 of the intervals to include the parameter and 5 to not include the parameter. B. The probability that the value of the parameter lies between the lower and upper bounds of the interval is 95%....
Find the 98% confidence interval for the difference between two means based on this information about two samples. Assume independent samples from normal populations. (Use conservative degrees of freedom.) (Give your answers correct to two decimal places.) Sample Number Mean Std. Dev. 1 18 40 30 2 17 28 25 Lower : ??? Upper: ???
Find the 98% confidence interval for the difference between two means based on this information about two samples. Assume independent samples from normal populations. (Use conservative degrees of freedom.) (Give your answers correct to two decimal places.) Sample Number Mean Std. Dev. 1 25 31 20 2 13 26 32 Lower Limit Upper Limit
uestion 4 Calculate the 95% confidence interval for the difference (mul-mu2) of two population means given the following sampling results. Population 1: sample size = 19, sample mean = 22.82, sample standard deviation = 4.81. Population 2: sample size = 5, sample mean = 12.06, sample standard deviation = 3.75 Your answer: 9.60 < mul-mu2 < 11.93 . 6.02 < mul-muz < 15.51 6.44 < mul-mu2 <15.08 6.37 < mul-mu2 < 15.16 1.82 < mul-mu2 < 19.71 9.58 < mul-mu2...
Calculate the 95% confidence interval for the difference (mul-mu2) of two population means given the following sampling results. Population 1: sample size = 15, sample mean = 30.95, sample standard deviation = 4.07. Population 2: sample size = 11, sample mean = 14.38, sample standard deviation = 4.07. Your answer: O 13.79 < mul-mu2 < 19.36 13.97 < mul-mu2 < 19.18 O 12.83 < mul-mu2 <20.32 11.14 <mul-mu2 < 22.01 O 16.31 <mul-mu2 < 16.84 O 11.33 < mul-mu2<21.82 o...
Confidence Intervals 9. Construct a 95 % confidence interval for the population mean, . In a random sample of 32 computers, the mean repair cost was $143 with a sample standard deviation of $35 (Section 6.2) Margin of error, E. <με. Confidence Interval: O Suppose you did some research on repair costs for computers and found that the population standard deviation, a,- $35. Use the normal distribution to construct a 95% confidence interval the population mean, u. Compare the results....
suppose that from a sample size of 16, a 95% confidence interval of (12,18) for the mean has been obtained determine x and s respectivly
Calculate a 95% confidence interval for the standard deviation of Total Cost for all customers (assuming that Total Cost follows normal distribution). n 400 Variance $9,481.51 Std Dev 97.37 Sample mean $153.82