Question

Given a triangle with angle A = 93 degrees and sides a = 33 and b = 16. Find side c. c= Using the Law of Sines to solve the triangle if a = 13°,B= 23°, a = 20. Round to two decimal places. As in the text, (a, a), (B, b) and ( c) are angle-side opposite pairs. If no such triangle exists, enter DNE in each answer box. Preview degrees b= Preview Preview Due in 1 hours, 36 minutes. Due Sat 04/25 Using the Law of Sines to solve the triangle if a = 13°, B = 23°, a = 20. Round to two decimal places. As in the text, (a, a), (B, b) and (y,c) are angle-side opposite pairs. If no such triangle exists, enter DNE in each answer box. degrees Preview Preview Preview

Answer 1

,
so. Given : : 93 R A=980 a=33 6=16 from finnule SinCA) sin(k) – fine) >K Finch), 0.0202 8in (B) 200302 ET 0.0302 x ba fin (B) Pin(B) = 0.4832 B2 fin'(0.4832) B= 25.99 in AABC AARAC = 180°. AtR+ į - 1889 -28.9-93 2:58.1 Since) -0.0302 sin( 58.1) 0.0302 ez 28.11

Now Now as = 13" p=23" a= 20 a- vo RON ... sin rule sinca). Sin (B) = sin() sin (13) = sin(23) .2016 h = sin(23) x20. sin( 13 ) b = 34.73 INAABC LA +48 +66 =180° Now fa 180-(Q+B) = 180.- 13-23 = 144º. Sin(RB) Sin (144) 20. C : Sin 144) x20 ģin (13) C = 52.25 (2,) 13,20) CB. b) = (23; 34.73) (FC) = (144, 52-25) Triangle existe.