Question

Questions 16 through 24: Member AD in the assembly of Fig 4 is too short by an amount d. It must be stretched downward to be pinned at point A to the rigid member ABC. Member BE has that same cross- sectional area A and Young's Modulus E. (016 to 020: 2 points each, Q21 to Q24:1 point each) L+d rigid 16) The downward force that must be applied onto point A of member AD in order to stretch it enough to pin it to rigid member ABC is dl EA EAL b) Fig 4 (Questions 16-24) EA EAd d) 17) The corresponding strain in AD as it is stretched to point A on the rigid member ABC is a) b) c d)

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Answer 1

We kmau hat ness setnal area x Young medudus Bt, Change neenabl : 、Applied tre- d F E Ad CRangs in Length d Orginal Lenat L 1 8

Moment and Moment stres ir E and p=2F d2